document.write( "Question 306555: Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 10%.
\n" ); document.write( "His total annual income from the two investments was $3980. How much was invested at 10%? \n" ); document.write( "
Algebra.Com's Answer #219364 by mananth(16949)\"\" \"About 
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Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 10%.
\n" ); document.write( "His total annual income from the two investments was $3980. How much was invested at 10%?\r
\n" ); document.write( "\n" ); document.write( "let the amount invested at 7% be $x\r
\n" ); document.write( "\n" ); document.write( "The interest accrued from this will be 0.07x\r
\n" ); document.write( "\n" ); document.write( "The amount invested at 10% = 2x+2000\r
\n" ); document.write( "\n" ); document.write( "The interest acrued from this will be 0.1(2x+2000)\r
\n" ); document.write( "\n" ); document.write( "The total interest he got was $3980\r
\n" ); document.write( "\n" ); document.write( "0.07x + 0.1(2x+2000)= 3980\r
\n" ); document.write( "\n" ); document.write( "0.07x +0.2x+ 200 = 3980\r
\n" ); document.write( "\n" ); document.write( "0.0.27x= 14000\r
\n" ); document.write( "\n" ); document.write( "x= 14000 amount invested at 7%\r
\n" ); document.write( "\n" ); document.write( "the amount invested at 10% is 2x+2000\r
\n" ); document.write( "\n" ); document.write( "2*14000 + 2000= $30000\r
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