document.write( "Question 306405: What is the radius if the circumference is:\r
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document.write( "4x-10pi \r
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document.write( "(5/2)pi \r
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document.write( "14pi \r
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document.write( "(x + y)pi \r
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document.write( "I have previously completed these problems. However, my answers were deemed incorrect. I would be grateful for assistance. Cheers! \n" );
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Algebra.Com's Answer #219336 by checkley77(12844) ![]() You can put this solution on YOUR website! C=2PI*R \n" ); document.write( "4x-10pi \n" ); document.write( "4X-10PI=2PI*R \n" ); document.write( "(4X-10PI)/2=PI*R \n" ); document.write( "2X-5PI=PI*R \n" ); document.write( "R=(2X-5PI)/PI ANS. \n" ); document.write( "------------- \n" ); document.write( "(5/2)pi \n" ); document.write( "5PI/2=2PI*R \n" ); document.write( "R=(5PI/2)/2PI \n" ); document.write( "R=(5PI/2)(1/2PI) \n" ); document.write( "R=5PI/4PI \n" ); document.write( "R=5/4 ANS. \n" ); document.write( "------------- \n" ); document.write( "14pi \n" ); document.write( "14PI=2PI*R \n" ); document.write( "R=14PI/2PI \n" ); document.write( "R=7 ANS. \n" ); document.write( "------------ \n" ); document.write( "(x + y)pi \n" ); document.write( "(X+Y)PI=2PI*R \n" ); document.write( "R=(X+Y)PI/2PI \n" ); document.write( "R=(X+Y)/2 ANS. \n" ); document.write( " \n" ); document.write( " |