document.write( "Question 306365: Someone drove to the city at a rate of 50 km/h. He returned along the same route at a faster speed, making his average rate for the round trip 60 km/h.
\n" ); document.write( "What was his returning speed?
\n" ); document.write( "

Algebra.Com's Answer #219268 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Ave speed = (total distance)/(total time)
\n" ); document.write( "Let \"d\" = distance to city
\n" ); document.write( "Let \"s\" = his returning speed
\n" ); document.write( "given:
\n" ); document.write( "\"d%2F50\" = time to get to city
\n" ); document.write( "\"%28d+%2B+d%29%2F%28d%2F50+%2B+d%2Fs%29+=+60\"
\n" ); document.write( "\"2d+=+60%2A%28d%2F50+%2B+d%2Fs%29\"
\n" ); document.write( "\"2d+=+60d%281%2F50+%2B+1%2Fs%29\"
\n" ); document.write( "\"1%2F30+=+1%2F50+%2B+1%2Fs\"
\n" ); document.write( "Multiply both sides by \"150s\"
\n" ); document.write( "\"5s+=+3s+%2B+150\"
\n" ); document.write( "\"2s+=+150\"
\n" ); document.write( "\"s+=+75\"
\n" ); document.write( "His return speed was 75 mi/hr
\n" ); document.write( "
\n" );