document.write( "Question 306282: marcus invested a sum of money at 5%.he invested an amount of $250 more than the first amount at 6%. if the annual income from both investments totaled $59, how much did he invest at each rate?
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\n" ); document.write( "if i set my problem up like this is it correct?\r
\n" ); document.write( "\n" ); document.write( ".05x+.06x+15=59 i got an answer of x= 400\r
\n" ); document.write( "\n" ); document.write( "if this is not correct could you help me set it up?
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Algebra.Com's Answer #219244 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
I got exactly the same answer for x.
\n" ); document.write( "The initial set-up looks like this...
\n" ); document.write( "0.05x+(x+$250)(0.06) = $59 then...
\n" ); document.write( "0.05x+0.06x+$15 = $59 subtracting $15 from both sides...
\n" ); document.write( "0.11x = $44 Dividing by 0.11...
\n" ); document.write( "x = $400 and x+$250 = $650
\n" ); document.write( "So Marcus invested $400 at 5% and $650 at 6%
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