document.write( "Question 306282: marcus invested a sum of money at 5%.he invested an amount of $250 more than the first amount at 6%. if the annual income from both investments totaled $59, how much did he invest at each rate?
\n" );
document.write( "
\n" );
document.write( "if i set my problem up like this is it correct?\r
\n" );
document.write( "\n" );
document.write( ".05x+.06x+15=59 i got an answer of x= 400\r
\n" );
document.write( "\n" );
document.write( "if this is not correct could you help me set it up? \n" );
document.write( "
Algebra.Com's Answer #219244 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! I got exactly the same answer for x. \n" ); document.write( "The initial set-up looks like this... \n" ); document.write( "0.05x+(x+$250)(0.06) = $59 then... \n" ); document.write( "0.05x+0.06x+$15 = $59 subtracting $15 from both sides... \n" ); document.write( "0.11x = $44 Dividing by 0.11... \n" ); document.write( "x = $400 and x+$250 = $650 \n" ); document.write( "So Marcus invested $400 at 5% and $650 at 6% \n" ); document.write( " |