document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306259>Question 306259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of angle X is 12 less than twice the measure of angle Y. If angle X and angle Y are supplementary angles, find the measure of angle X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219219 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=2Y+12<BR>\n" );
document.write( "X+Y=180<BR>\n" );
document.write( "X=180-Y<BR>\n" );
document.write( "2Y+12=180-Y<BR>\n" );
document.write( "2Y+Y=180-12<BR>\n" );
document.write( "3Y=168<BR>\n" );
document.write( "Y=168/3<BR>\n" );
document.write( "Y=56 ANS.<BR>\n" );
document.write( "X+56=180<BR>\n" );
document.write( "X=180-56<BR>\n" );
document.write( "X=124 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "124=2*56+12<BR>\n" );
document.write( "124=112+12<BR>\n" );
document.write( "124=124<BR>\n" );
document.write( "56+124=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );