document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306255>Question 306255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to arrive at the answer to the following problem?\r<BR>\n" );
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document.write( "2 divided by the 6th root of 81.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219199 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to arrive at the answer to the following problem? <BR>\n" );
document.write( "2 divided by the 6th root of 81. <BR>\n" );
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document.write( "It's good to eliminate radicals in the denominator, makes it much easier to add and subtract things.  This is usually called \"simplifying\" the expression.<BR>\n" );
document.write( "2/6th rt(81) <BR>\n" );
document.write( "= 2/(cube root(9))<BR>\n" );
document.write( "= 2*(cube root(81))/9<BR>\n" );
document.write( "= 2*(cr(27) * cr(3))/9<BR>\n" );
document.write( "= 2*3*(cr(3))/9<BR>\n" );
document.write( "= 2cuberoot(3)/3<BR>\n" );
document.write( "Using a calculator,<BR>\n" );
document.write( "=~ 0.961499713 </SPAN>\n" );
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