document.write( "Question 306077: how much pure acid should be mixed with 4 gallons of 60% acid soultion in order to get an 80% acid solution? \n" ); document.write( "

Algebra.Com's Answer #219150 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"x\"$ = gallons of pure acid to add
\n" ); document.write( " $\"%28x+%2B+.6%2A4%29%2F%28x+%2B+4%29+=+.8\"$
\n" ); document.write( " $\"x+%2B+2.4+=+.8%2A%28x+%2B+4%29\"$
\n" ); document.write( " $\"x+%2B+2.4+=+.8x+%2B+3.2\"$
\n" ); document.write( " $\".2x+=+.8\"$
\n" ); document.write( " $\"x+=+4\"$
\n" ); document.write( "4 gallons of pure acid must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"%284+%2B+.6%2A4%29%2F%284+%2B+4%29+=+.8\"$
\n" ); document.write( " $\"6.4%2F8+=+.8\"$
\n" ); document.write( " $\".8+=+.8\"$
\n" ); document.write( "OK \n" ); document.write( "

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