document.write( "Question 306138: How many mg of a metal containing 45% nickel must be combined with 6mg of pure nickel to form an alloy containing 78% nickel? \n" ); document.write( "
Algebra.Com's Answer #219141 by nospmoht(3)\"\" \"About 
You can put this solution on YOUR website!
Aight, first you have to sort your information. You have:
\n" ); document.write( ".45x (represents an unknown amount of 45% nickel)
\n" ); document.write( "1(6) (represents 6 mg of 100% nickel)
\n" ); document.write( ".78(6+x) (represents 6 mg plus an unkown amount of 78% nickel)\r
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\n" ); document.write( "\n" ); document.write( "Then just make an equation. In 'mixture' word problems, the outcome or mixture will be on one side and the two substances being mixed will be on the other. This is how the equation for the problem would look:
\n" ); document.write( ".45x +1(6)=.78(6+x)\r
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\n" ); document.write( "\n" ); document.write( "Solve for x:
\n" ); document.write( ".45x +1(6)=.78(6+x)
\n" ); document.write( ".45x +6 =4.68 + .78x
\n" ); document.write( "1.32 = .33x
\n" ); document.write( "4 = x\r
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\n" ); document.write( "\n" ); document.write( "Then you plug it into the unknown information (shown at the top. So:
\n" ); document.write( ".45x now is .45(4), which equals 1.8 mgs\r
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\n" ); document.write( "\n" ); document.write( "Answer: 1.8 mgs of 45% nickel mixed with 6 mgs of 100% nickel will result in 7.8 mgs of 78% nickel.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helped you man. Good luck :) \n" ); document.write( "
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