document.write( "Question 306138: How many mg of a metal containing 45% nickel must be combined with 6mg of pure nickel to form an alloy containing 78% nickel? \n" ); document.write( "

Algebra.Com's Answer #219137 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"x\"$ = mg of metal containing 45% nickel to be added
\n" ); document.write( " $\".45x\"$ = nickel content of added metal
\n" ); document.write( "In words:
\n" ); document.write( "(mg of nickel in final alloy)/(mg of final alloy) = 78%
\n" ); document.write( " $\"%28.45x+%2B+6%29%2F%28x+%2B+6%29+=+.78\"$
\n" ); document.write( " $\".45x+%2B+6+=+.78%2A%28x+%2B+6%29\"$
\n" ); document.write( " $\".45x+%2B+6+=+.78x+%2B+4.68\"$
\n" ); document.write( " $\".78x+-+.45x+=+6+-+4.68\"$
\n" ); document.write( " $\".33x+=+1.32\"$
\n" ); document.write( " $\"x+=+4\"$
\n" ); document.write( "4 mg of 45% nickel metal must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"%28.45x+%2B+6%29%2F%28x+%2B+6%29+=+.78\"$
\n" ); document.write( " $\"%28.45%2A4+%2B+6%29%2F%284+%2B+6%29+=+.78\"$
\n" ); document.write( " $\"%281.8+%2B+6%29%2F10+=+.78\"$
\n" ); document.write( " $\"7.8%2F10+=+.78\"$
\n" ); document.write( " $\".78+=+.78\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );