document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305976>Question 305976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+6x+45=0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219063 by </B><A HREF=/tutors/aboutme.mpl?userid=sweetlipstogo><B>sweetlipstogo(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sweetlipstogo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since 2x and 6x are like terms, add 6x to 2x to get 8x<BR>\n" );
document.write( "8x+45=0<BR>\n" );
document.write( "Since 45 does not contain the variable to solve for, move it to the right hand side of the equation by subtracting 45 from both sides.<BR>\n" );
document.write( "8x=-45<BR>\n" );
document.write( "Divide each term in the equation by 8.<BR>\n" );
document.write( "8x/8=-45/8<BR>\n" );
document.write( "Simplify the left hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "x= -45/8 </SPAN>\n" );
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