document.write( "Question 305980: Hi, I'm a high school senior and need help solving a True Equation problem. I must use 0-9 to make the equation and must use each digit once.
\n" ); document.write( "Here is the problem (There are four problems in one question);
\n" ); document.write( " 2+_=_
\n" ); document.write( " _x_=__(This one needs a double digit, i.e 22 or something)
\n" ); document.write( " _/_=2
\n" ); document.write( " _-1=_\r
\n" ); document.write( "\n" ); document.write( "I must use the numbers only once. I do not believe that the 2 and 1 count against the 0-9 numbers. So far I thought that this would work;\r
\n" ); document.write( "\n" ); document.write( "4/2=2 but now I got stuck on the rest. Originally the whole problem read;\r
\n" ); document.write( "\n" ); document.write( "2+6=8
\n" ); document.write( "5x7=12
\n" ); document.write( "4/2=2
\n" ); document.write( "_-1=_\r
\n" ); document.write( "\n" ); document.write( "But I don't think that works. Can you help me please?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #219059 by themathtutor2009(81) $\"\"$ $\"About$

You can put this solution on YOUR website!
One possible solution:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2+7=9
\n" ); document.write( "8 x 5=4 0
\n" ); document.write( "6/3=2
\n" ); document.write( "2-1=1
\n" ); document.write( " \n" ); document.write( "

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