document.write( "Question 305978: The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field? \n" ); document.write( "
Algebra.Com's Answer #219051 by checkley77(12844)\"\" \"About 
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P=2L+2W
\n" ); document.write( "L=2W+2
\n" ); document.write( "244=2(2W+2)+2W
\n" ); document.write( "244=4W+4+2W
\n" ); document.write( "244=6W+4
\n" ); document.write( "6W=244-4
\n" ); document.write( "6W=240
\n" ); document.write( "W=240/6
\n" ); document.write( "W=40 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*40+2=80+2=82 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "244=2*82+2*40
\n" ); document.write( "244=164+80
\n" ); document.write( "244=244
\n" ); document.write( "
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