document.write( "Question 305978: The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field? \n" ); document.write( "
Algebra.Com's Answer #219051 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=2W+2 \n" ); document.write( "244=2(2W+2)+2W \n" ); document.write( "244=4W+4+2W \n" ); document.write( "244=6W+4 \n" ); document.write( "6W=244-4 \n" ); document.write( "6W=240 \n" ); document.write( "W=240/6 \n" ); document.write( "W=40 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*40+2=80+2=82 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "244=2*82+2*40 \n" ); document.write( "244=164+80 \n" ); document.write( "244=244 \n" ); document.write( " |