document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35661>Question 35661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex and focus of the Parabola whose equation is 4(y-2) = (x-4) ^2.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21904 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4(y-2) = (x-4) ^2<BR>\n" );
document.write( "(y-2) = (1/4)(x-4)^2<BR>\n" );
document.write( "y=(1/4)(x-4)^2+2<BR>\n" );
document.write( "In y=a(x-h)^2+k the vertex is (h,k), so the vertex for this equation is (4,2)<BR>\n" );
document.write( "The length from vertex to focus is: p=(1/4a)=(1/1)=1, so the focu is (4,3)<BR>\n" );
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