document.write( "Question 305917: one car travels 300 miles while a car going ten miles faster travels 350. How fast is the first car going? \n" ); document.write( "
Algebra.Com's Answer #219039 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "300=RT \n" ); document.write( "350=(R+10)T \n" ); document.write( "T=300/R \n" ); document.write( "350=(R+10)300/R \n" ); document.write( "350=(300R+3,000)/R \n" ); document.write( "350R=300R+3,000 \n" ); document.write( "350R-300R=3,000 \n" ); document.write( "50R=3,000 \n" ); document.write( "R=3,000/50 \n" ); document.write( "R=60 MPH. FOR THE SLOWER CAR. \n" ); document.write( "60+10=70 MPH FOR THE FASTER CAR. \n" ); document.write( " |