document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305838>Question 305838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation of the line having the given characteristics\r<BR>\n" );
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document.write( "X-intercept = 2; passing through (4,-5)\r<BR>\n" );
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document.write( "also\r<BR>\n" );
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document.write( "find an equation of the line having the given characteristics\r<BR>\n" );
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document.write( "perpindicular to the line 3x - y + 4 = 0; passing through (-2,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218975 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218975\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find an equation of the line having the given characteristics<BR>\n" );
document.write( "X-intercept = 2; passing through (4,-5)<BR>\n" );
document.write( "Assign the values as follows<BR>\n" );
document.write( "x1=2, y1=0, (from the x intercept)<BR>\n" );
document.write( "x2=4, y2=-5<BR>\n" );
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document.write( "Find the slope<BR>\n" );
document.write( "m = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-5+-+0%29%2F%284+-+2%29 ALIGN=MIDDLE  ALT=\"%28-5+-+0%29%2F%284+-+2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-5%29%2F2 ALIGN=MIDDLE  ALT=\"%28-5%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = -2.5<BR>\n" );
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document.write( "Use the point/slope formula; y - y1 = m(x - x1)<BR>\n" );
document.write( "y - (-5) = -2.5(x - 4)<BR>\n" );
document.write( "y + 5 = -2.5x + 10<BR>\n" );
document.write( "y = -2.5x + 10 - 5<BR>\n" );
document.write( "y = -2.5x + 5; is the equation passing thru 4,-5, with x intercept of 2<BR>\n" );
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document.write( "also<BR>\n" );
document.write( "find an equation of the line having the given characteristics<BR>\n" );
document.write( "perpendicular to the line 3x - y + 4 = 0; passing through (-2,2)<BR>\n" );
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document.write( "Arrange the equation in the slope/intercept form to find the slope<BR>\n" );
document.write( "3x - y + 4 = 0; <BR>\n" );
document.write( "-y = -3x - 4<BR>\n" );
document.write( "Multiply by -1<BR>\n" );
document.write( "y = 3x + 4<BR>\n" );
document.write( "m1 = 3 is the slope<BR>\n" );
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document.write( "Slope relationship to parallel line: m1*m2 = -1, therefore<BR>\n" );
document.write( "3*m2 = -1<BR>\n" );
document.write( "m2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >; slope of the parallel line<BR>\n" );
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document.write( "Use the point/slope formula: y - y1 = m(x - x1) where x1=-2, y1=2<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >(x - (-2))<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >(x + 2)<BR>\n" );
document.write( "y - 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 2<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2F3 ALIGN=MIDDLE  ALT=\"6%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >; is the equation of the parallel line </SPAN>\n" );
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