document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305882>Question 305882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If A @ B means  2A-3B, calculate the value of (2@1) + (3@2) ?\r<BR>\n" );
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document.write( "A) 5   B) 8  C) 6  D) 1  E) 3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218963 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If A @ B means 2A-3B, calculate the value of (2@1) + (3@2) ? <BR>\n" );
document.write( "A) 5 B) 8 C) 6 D) 1 E) 3 \r<BR>\n" );
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document.write( "A@B = 2A - 3B<BR>\n" );
document.write( "2@1 = 2(2) - 3(1) = 4 - 3 = 1<BR>\n" );
document.write( "3@2 = 2(3) - 3(2) = 6 - 6 = 0<BR>\n" );
document.write( "(2@1) + (3@2) = 1 + 0 = 1\r<BR>\n" );
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document.write( "answer is D)1<BR>\n" );
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