document.write( "Question 305680: ONE SAMPLE HYPOTHESIS TEST FOR PROPORTION: The Webster University librarian believes that more than 60% of the books checked out by students was fictional material. In a random sample of 1000 students who checked books out in the last year, 628 checked out fictional material. What can one conclude about the librarian's hypothesis at a level of significance of .05?
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document.write( "2a) Direction = UPPER TAILED / LOWER TAILED / 2-TAILED (circle one)
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document.write( "2b) P-value = ________________
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document.write( "2c) REJECT THE NULL or DO NOT REJECT THE NULL? (circle one)
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document.write( "2d) Can we conclude the librarian’s claim is correct? YES or NO (circle one)
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Algebra.Com's Answer #218945 by stanbon(75887) ![]() You can put this solution on YOUR website! ONE SAMPLE HYPOTHESIS TEST FOR PROPORTION: The Webster University librarian believes that more than 60% of the books checked out by students was fictional material. In a random sample of 1000 students who checked books out in the last year, 628 checked out fictional material. What can one conclude about the librarian's hypothesis at a level of significance of .05? \n" ); document.write( "------ \n" ); document.write( "2a) Direction = UPPER TAILED / LOWER TAILED / 2-TAILED (circle one) \n" ); document.write( "Ans: The key words are \"more than\"; so the test is right tail. \n" ); document.write( "-------- \n" ); document.write( "2b) P-value = ________________ \n" ); document.write( "p-hat = 628/1000 = 0.628 \n" ); document.write( "-- \n" ); document.write( "test stat: z(0.628)=(0.628-0.600)/sqrt(0.6*0.4/1000) = 1.8074 \n" ); document.write( "p-value = P(z > 1.8074) = 0.0354 \n" ); document.write( "------------------------------- \n" ); document.write( "2c) REJECT THE NULL or DO NOT REJECT THE NULL? (circle one) \n" ); document.write( "Since the p-value is less than 5%, reject Ho. \n" ); document.write( "------- \n" ); document.write( "2d) Can we conclude the librarian’s claim is correct? YES or NO (circle one) \n" ); document.write( "YES \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |