document.write( "Question 305737: Please help me to solve this word problem. We have just started this new section and I just can't solve it. \r
\n" ); document.write( "\n" ); document.write( "Water from a fire hose is sprayed on a fire that is coming from a window. The window is 15m up the side of a wall. The equation H=-0.011x^2+.99x +1.6 models the height of the jet of water, H, and the horizontal distance it can travel form the nozzle, x, both in meters. What is the maximum height that the water can reach? and how far back could a firefighter stand, but still have the water reach the window?
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Algebra.Com's Answer #218918 by nerdybill(7384)\"\" \"About 
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Water from a fire hose is sprayed on a fire that is coming from a window. The window is 15m up the side of a wall. The equation H=-0.011x^2+.99x +1.6 models the height of the jet of water, H, and the horizontal distance it can travel form the nozzle, x, both in meters. What is the maximum height that the water can reach? and how far back could a firefighter stand, but still have the water reach the window?
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\n" ); document.write( "The given equation:
\n" ); document.write( "H=-0.011x^2+.99x +1.6
\n" ); document.write( "Is a parabola that opens downwards.
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\n" ); document.write( "What is the maximum height that the water can reach?
\n" ); document.write( "This entails finding the vertex.
\n" ); document.write( "Axis of symmetry = -b/(2a) = -.99/(2*(-0.011))
\n" ); document.write( "Axis of symmetry = .99/0.022
\n" ); document.write( "Axis of symmetry = 45 meters
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\n" ); document.write( "H=-0.011x^2+.99x +1.6
\n" ); document.write( "H=-0.011(45^2)+.99(45) +1.6
\n" ); document.write( "H= 23.875 meters (maximum height)
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\n" ); document.write( "Distance from wall:
\n" ); document.write( "45 meters\r
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