document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35715>Question 35715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular dog kennel made using the wall of a barn and 24m of wire (to form the other three sides of the kennel). if the area of the kennel is 70m squared, find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21890 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X*Y=70 <BR>\n" );
document.write( "2Y+X=24 THUS X=24-2Y SUBSTITUTING 24-2Y FOR X IN THE FIRST FORMULA  WE GET\r<BR>\n" );
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document.write( "(24-2Y)Y=70 OR 24Y-2Y~2-70=0 OR 2Y~2-24Y+70=O OR Y~2-12Y+35 OR\r<BR>\n" );
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document.write( "(Y-7)(Y-5)=0 OR Y=7 & Y=5 SUBSTITUTING 7 FOR Y IN EQUATION 1\r<BR>\n" );
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document.write( "7*X=70 OR X=70/10 OR X=7 THUS 2*7+10=24 THEN 24=24\r<BR>\n" );
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document.write( "5*X=70 OR X=70/5 OR X=14 THUS 2*5+14=24 THEN 24=24\r<BR>\n" );
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document.write( "THERE ARE TWO SETS OF SOLUTIONS X=7,Y=10 & X=5,Y=14 \r<BR>\n" );
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