document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305766>Question 305766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle field id twice it's breadth. If the perimeter of the field is 72m . Find it's area  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218887 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle field is twice it's breadth. If the perimeter of the field is 72m . Find it's area <BR>\n" );
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document.write( "Equations from the narrative:<BR>\n" );
document.write( "L = 2W<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Perimeter = 2(L+W) = 72<BR>\n" );
document.write( "L+W = 36<BR>\n" );
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document.write( "Substitute for \"L\" and solve for \"W\":<BR>\n" );
document.write( "2W+W = 36<BR>\n" );
document.write( "W = 12<BR>\n" );
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document.write( "Since L = 2W, L = 6<BR>\n" );
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document.write( "Area = 6*12 = 72 sq meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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