document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305756>Question 305756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of  a two digit number is 15. If the digits are reversed, the result exceeds the original number by 9.Find the original number.<BR>\n" );
document.write( "I think the first equation is: x + y = 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218880 by </B><A HREF=/tutors/aboutme.mpl?userid=themathtutor2009><B>themathtutor2009(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=themathtutor2009><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=15<BR>\n" );
document.write( "10y+x=10x+y+9\r<BR>\n" );
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document.write( "x+y=15<BR>\n" );
document.write( "y=15-x\r<BR>\n" );
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document.write( "10y+x=10x+y+9<BR>\n" );
document.write( "10(15-x)+x=10x+15-x+9<BR>\n" );
document.write( "150-10x+x=10x+15-x+9<BR>\n" );
document.write( "150-9x=9x+24<BR>\n" );
document.write( "150-24=9x+9x<BR>\n" );
document.write( "126=18x<BR>\n" );
document.write( "126/18=x<BR>\n" );
document.write( "7=x<BR>\n" );
document.write( "x=7\r<BR>\n" );
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document.write( "y=15-x=15-7=8\r<BR>\n" );
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document.write( "Answer: number is 78\r<BR>\n" );
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document.write( " </SPAN>\n" );
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