document.write( "Question 305770: If a and b are odd integers, which of the following must also be an odd integer?\r
\n" ); document.write( "\n" ); document.write( "I. (a + 1)b
\n" ); document.write( "II. II. (a + 1) + b
\n" ); document.write( "III. III. (a + 1) – b\r
\n" ); document.write( "\n" ); document.write( "a) I only b) II only c) III only d) I & II e) II & III \n" ); document.write( "

Algebra.Com's Answer #218877 by toidayma(44) $\"\"$ $\"About$

You can put this solution on YOUR website!
You should know the basic formulas of odd and even number:
\n" ); document.write( "odd + odd = even,
\n" ); document.write( "odd - odd = even,
\n" ); document.write( "odd + even = odd,
\n" ); document.write( "odd - even = odd,
\n" ); document.write( "even + even = even,
\n" ); document.write( "even - even = even,
\n" ); document.write( "odd*odd = odd,
\n" ); document.write( "odd *even = even and
\n" ); document.write( "even * even = even.
\n" ); document.write( "I. With(a+1)*b, since a is odd, a + 1 is even, and since b is odd, we have (a+1)*b = even.
\n" ); document.write( "II. With (a+1) + b, since a is odd, a + 1 is even, and since b is odd, we have (a+1) + b is odd.
\n" ); document.write( "III. With (a+1) - b, since a is odd, a + 1 is even, and since b is odd, we have (a+1) - b is odd.
\n" ); document.write( "Therefore, II and III are odd, thus the answer is e>II & III \n" ); document.write( "

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