document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305753>Question 305753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of  a two digit number is 15. If the digits are reversed, the result exceeds the original number by 9.Find the original number.<BR>\n" );
document.write( "I think the first equation is: x + y = 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218868 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Let the digits in the units place be y<BR>\n" );
document.write( "in tens place be x\r<BR>\n" );
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document.write( "when reversed\r<BR>\n" );
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document.write( "10y+x-9=10x+y\r<BR>\n" );
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document.write( "9y-9x=9<BR>\n" );
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document.write( "y-x=1<BR>\n" );
document.write( "y+x=15\r<BR>\n" );
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document.write( "2y=16\r<BR>\n" );
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document.write( "y=8\r<BR>\n" );
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document.write( "x= 7\r<BR>\n" );
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document.write( "The number is 78 </SPAN>\n" );
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