document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305678>Question 305678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: Rectangle ABCD, E is the midpoint of line BC<BR>\n" );
document.write( "Prove: line AE is congruent to line DE\r<BR>\n" );
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document.write( "I know this need a pic therefore I 'm going to try to describe it as best as I can alright so we have an ABCD rectangle. Start at angle A being on very top of left hand side corner, then the rest of angles BCD work it way by clockwise direction.\r<BR>\n" );
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document.write( "From angle A and D (which is on left side) there is two line that look like an A letter (except without a line in between) drawn toward the right side-known as midpoint E ( which cut line BC in half)\r<BR>\n" );
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document.write( "that basically it please help me, this is due tomorrow and I know this is a bad time but I reall ycant do the problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218854 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AB congruent to CD<BR>\n" );
document.write( "___ opposite sides of parallelogram congruent\r<BR>\n" );
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document.write( "BE congruent to EC<BR>\n" );
document.write( "___ definition of midpoint\r<BR>\n" );
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document.write( "angle B congruent to angle C<BR>\n" );
document.write( "___ definition of rectangle\r<BR>\n" );
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document.write( "triangle ABE congruent to triangle DCE <BR>\n" );
document.write( "___ S-A-S\r<BR>\n" );
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document.write( "AE is congruent to DE<BR>\n" );
document.write( "___CPCTC (corresponding parts of congruent triangles are congruent)\r<BR>\n" );
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document.write( "this may need a little \"neatening up\", but it is the core of the proof </SPAN>\n" );
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