document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305674>Question 305674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimensions of a rectangle with perimeter 36 square units and area 65 square units.whitch of the following could be the dimensions of the rectangles?can you please explain this to me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218850 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter 36\r<BR>\n" );
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document.write( "area 65\r<BR>\n" );
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document.write( "2L+2W= 36   ( perimeter )\r<BR>\n" );
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document.write( "L*W = 65   ( area)\r<BR>\n" );
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document.write( "L= 65/w\r<BR>\n" );
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document.write( "2L+2W= 36\r<BR>\n" );
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document.write( "2* 65 /W + 2W= 36\r<BR>\n" );
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document.write( "130+2W^2 / W = 36\r<BR>\n" );
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document.write( "130 +2W^2 =36W\r<BR>\n" );
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document.write( "2W^2-36W+130=0<BR>\n" );
document.write( "2(W^2-18W+65)=0\r<BR>\n" );
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document.write( "2(w-13)(W-5)=0\r<BR>\n" );
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document.write( "W= 13 Or 5\r<BR>\n" );
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document.write( "The dimensions are 13 by 5 units </SPAN>\n" );
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