document.write( "Question 4634: If you know the area in square feet of a rectangle but don't know what the perimeter is how can you figure that out? I know that you can use the formula 2L + 2W, but I am trying to figure out how 300 ft of fencing can go around a rectangle that has an area of 5000 square ft. \n" ); document.write( "
Algebra.Com's Answer #2188 by arunpaul(104)\"\" \"About 
You can put this solution on YOUR website!
let the side of rectangle are L and B
\n" ); document.write( "as per question L*B = 5000 sft
\n" ); document.write( "again 2(L+B) = 300 - eq1
\n" ); document.write( "again L = 5000/B
\n" ); document.write( "then put the value in the equation 1
\n" ); document.write( "then 2((5000/B)+B)= 300
\n" ); document.write( "or (10000/B)+2B = 300
\n" ); document.write( "or (10000/B) = 300-2B
\n" ); document.write( "or 10000= 300B -2B^2
\n" ); document.write( "or 5000=150B -B^2
\n" ); document.write( "solve the equation by trial and error or by the equation\r
\n" ); document.write( "\n" ); document.write( "x1,2 = -b ± sqrt( b2-4ac )
\n" ); document.write( " ------------------
\n" ); document.write( " 2a
\n" ); document.write( "here the equation is
\n" ); document.write( "B^2-150B+5000 = 0\r
\n" ); document.write( "\n" ); document.write( "so a= 1
\n" ); document.write( "b= 150
\n" ); document.write( "c=5000
\n" ); document.write( "putting thevalue
\n" ); document.write( "u can get the solution for B
\n" ); document.write( "such as
\n" ); document.write( "((-150)+sqrt(150^2-4*1*5000))/(2*1)
\n" ); document.write( "((-150)-sqrt(150^2-4*1*5000))/(2*1)
\n" ); document.write( "solving the above equation we get B = -10000 and -10150
\n" ); document.write( "so no real solution
\n" ); document.write( "that means your question is wrong
\n" ); document.write( "check my answer and mail again\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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