document.write( "Question 305543: Which of the following equations is developed while using completing the square to solve the equation x2 - 6x + 4 = 0\r
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document.write( "A. (x - 6)2 = 5
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document.write( "B. (x - 3)2 = 5
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document.write( "C. (x - 3)2 = -4
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document.write( "D. (x - 6)2 = -4 \r
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document.write( "please help! thank you very much. \n" );
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Algebra.Com's Answer #218776 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start with the given equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the lead coefficient is other than 1, divide by the lead coefficient.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Move the constant term to the RHS:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide the first term coefficient by 2 and square the result. Add this result to both sides. Minus 6 divided by 2 is minus 3. Minus 3 squared is 9. Add 9 to both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor the perfect square in the LHS:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the square root of both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finish solving\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |