document.write( "Question 305514: can someone help me figure out this word problem: is it possible for a rectangle with a primeter of 52 centimeters to have an area of 148.75 square centimeters? explain \n" ); document.write( "
Algebra.Com's Answer #218760 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of a rectangle is
\n" ); document.write( "\"P=2%2A%28L%2BW%29\"
\n" ); document.write( "The area of a rectangle is,
\n" ); document.write( "\"A=L%2AW\"
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\n" ); document.write( "\"2%2A%28L%2BW%29=52\"
\n" ); document.write( "\"L%2BW=26\"
\n" ); document.write( "\"L=26-W\"
\n" ); document.write( "Now plug that into the area formula,
\n" ); document.write( "\"L%2AW=148.25\"
\n" ); document.write( "\"%2826-W%29%2AW=148.25\"
\n" ); document.write( "\"26W-W%5E2=148.25\"
\n" ); document.write( "\"W%5E2-26W%2B148.25=0\"
\n" ); document.write( "Solve for W.
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+25%2C+-10%2C+10%2C+x%5E2-26x%2B148.25%29+\"
\n" ); document.write( "Looks like there are two positive solutions.
\n" ); document.write( "About W=8 and W=18, which gives L=18 and L=8 respectively or an approximately 8x18 cm rectangle.
\n" ); document.write( "So yes, you can have a rectangle of perimeter 52 cm and area of 148.25 sq. cm.
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