document.write( "Question 305491: Is this solvable?\r
\n" ); document.write( "\n" ); document.write( "A car travels with uniform speed. If it would have traveled 10 km/h faster, it would reach the destination 2 hours earlier and if it would have traveled 10km/h slower, it would reach the destination 3 hours later. What is the distance covered by car.
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Algebra.Com's Answer #218727 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A car travels with uniform speed. If it would have traveled 10 km/h faster, it would reach the destination 2 hours earlier and if it would have traveled 10km/h slower, it would reach the destination 3 hours later. What is the distance covered by car.
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\n" ); document.write( "Uniform speed DATA:
\n" ); document.write( "rate = r mph ; time = h hours ; distance = rh miles
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\n" ); document.write( "Slower speed DATA:
\n" ); document.write( "rate = r-10 mph ; time = h+3 hrs ; distance = (r-10)(h+3) miles
\n" ); document.write( "----------------
\n" ); document.write( "Faster speed DATA:
\n" ); document.write( "rate = r+10 mph ; time = h-2 hrs ; distance = (r+10)(h-2) miles
\n" ); document.write( "------------------------
\n" ); document.write( "Equations:
\n" ); document.write( "(r-10)(h+3) = rh
\n" ); document.write( "(r+10)(h-2) = rh
\n" ); document.write( "-------
\n" ); document.write( "rh +3r - 10h - 30 = rh
\n" ); document.write( "rh -2r + 10h - 20 = rh
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\n" ); document.write( "3r - 10h = 30
\n" ); document.write( "-2r+ 10h = 20
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\n" ); document.write( "Add to get: r = 50 mph
\n" ); document.write( "----
\n" ); document.write( "Slower speed = r-10 = 40 mph
\n" ); document.write( "Faster speed = r+10 = 60 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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