document.write( "Question 305491: Is this solvable?\r
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document.write( "A car travels with uniform speed. If it would have traveled 10 km/h faster, it would reach the destination 2 hours earlier and if it would have traveled 10km/h slower, it would reach the destination 3 hours later. What is the distance covered by car. \n" );
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Algebra.Com's Answer #218727 by stanbon(75887) ![]() You can put this solution on YOUR website! A car travels with uniform speed. If it would have traveled 10 km/h faster, it would reach the destination 2 hours earlier and if it would have traveled 10km/h slower, it would reach the destination 3 hours later. What is the distance covered by car. \n" ); document.write( "----------------- \n" ); document.write( "Uniform speed DATA: \n" ); document.write( "rate = r mph ; time = h hours ; distance = rh miles \n" ); document.write( "--------------------- \n" ); document.write( "Slower speed DATA: \n" ); document.write( "rate = r-10 mph ; time = h+3 hrs ; distance = (r-10)(h+3) miles \n" ); document.write( "---------------- \n" ); document.write( "Faster speed DATA: \n" ); document.write( "rate = r+10 mph ; time = h-2 hrs ; distance = (r+10)(h-2) miles \n" ); document.write( "------------------------ \n" ); document.write( "Equations: \n" ); document.write( "(r-10)(h+3) = rh \n" ); document.write( "(r+10)(h-2) = rh \n" ); document.write( "------- \n" ); document.write( "rh +3r - 10h - 30 = rh \n" ); document.write( "rh -2r + 10h - 20 = rh \n" ); document.write( "--------------------------- \n" ); document.write( "3r - 10h = 30 \n" ); document.write( "-2r+ 10h = 20 \n" ); document.write( "--------------------------- \n" ); document.write( "Add to get: r = 50 mph \n" ); document.write( "---- \n" ); document.write( "Slower speed = r-10 = 40 mph \n" ); document.write( "Faster speed = r+10 = 60 mph \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |