document.write( "Question 305465: Irving’s total cash was only $2.50. How many nickels and dimes would he have? Again, solve by the method of your choice.\r
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Algebra.Com's Answer #218726 by graphmatics(170) $\"\"$ $\"About$

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We assume that Irving only can have Nickels and dimes for his cash. Then if x is the number of Nickels and y is the number of dimes then it is clear that\r
\n" ); document.write( "\n" ); document.write( "5*x + 10*y = 250
\n" ); document.write( "so
\n" ); document.write( "y = -.5*x + 25
\n" ); document.write( "if we plot this equation we get:
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+0%2C+150%2C+0%2C+150%2C+-.5x%2B25%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "any integer (x,y) on the line is nickels and dimes collection that equals $2,50. When x=0, no nickels all dimes, y=25. When y = 0, no dimes all nickels, x = 50.
\n" ); document.write( "We can't have 1 nickel because there is no 49 dimes combination that when added to 5 cent equals $2.50. \n" ); document.write( "

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