document.write( "Question 305310: A rain gutter is made from sheets of aluminum that are 20 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are two different solutions to the problem. Round to the nearest tenth of an inch. Thank you for your help...I have been working hard and I am stuck!! Amber \n" ); document.write( "
Algebra.Com's Answer #218723 by ankor@dixie-net.com(22740)\"\" \"About 
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A rain gutter is made from sheets of aluminum that are 20 inches wide.
\n" ); document.write( " The edges are turned up to form right angles. Determine the depth of the gutter
\n" ); document.write( " that will allow a cross-sectional area of 13 square inches.
\n" ); document.write( "Show that there are two different solutions to the problem.
\n" ); document.write( " Round to the nearest tenth of an inch.
\n" ); document.write( ":
\n" ); document.write( "Let x = the depth of the gutter
\n" ); document.write( "Let y = the width of the gutter
\n" ); document.write( ":
\n" ); document.write( "This may illustrate an end view of the gutter: x|_y_|x
\n" ); document.write( "then
\n" ); document.write( "2x + y = 20 in; the width of the sheets of aluminum
\n" ); document.write( "y = (20-2x); use this form for substitution
\n" ); document.write( "and
\n" ); document.write( "x*y = 13 sq/in; (the cross sectional area of the end of the gutter)
\n" ); document.write( ":
\n" ); document.write( "Using the area equation replace y with (20-2x)
\n" ); document.write( "x*(20-2x) = 13
\n" ); document.write( "a quadratic equation
\n" ); document.write( "-2x^2 + 20x - 13 = 0
\n" ); document.write( "Solve for x (depth) using the quadratic formula
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "in this equation a=-2; b=20; c=-13
\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%2820%5E2+-+4%2A-2%2A-13+%29%29%2F%282%2A-2%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%28400+-+104%29%29%2F%28-4%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"x+=+%28-20+%2B-+sqrt%28296%29%29%2F%28-4%29+\"
\n" ); document.write( "two solutions
\n" ); document.write( "\"x+=+%28-20+%2B+17.2%29%2F%28-4%29+\"
\n" ); document.write( "x = \"%28-2.8%29%2F%28-4%29\"
\n" ); document.write( "x = +.7 inches
\n" ); document.write( "and
\n" ); document.write( "\"x+=+%28-20+-+17.2%29%2F%28-4%29+\"
\n" ); document.write( "x = \"%28-37.2%29%2F%28-4%29\"
\n" ); document.write( "x = +9.3 inches
\n" ); document.write( ":
\n" ); document.write( "If the depth is .7 inches
\n" ); document.write( "20 - 2(.7) = 18.6 in wide; check the area: .7*18.6 ~ 13 sq/in
\n" ); document.write( ":
\n" ); document.write( "and if the depth is 9.3 in
\n" ); document.write( "20 - 2(9.3) = 1.4 in wide; check the area: 9.3*1.4 ~ 13 sq/in also \n" ); document.write( "
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