document.write( "Question 35754: (x+4)/10=6/(x-3) \n" ); document.write( "
Algebra.Com's Answer #21871 by kev82(151)![]() ![]() ![]() You can put this solution on YOUR website! Hi,\r \n" ); document.write( "\n" ); document.write( "We want to find x. At the moment x is in the numerator of one fraction, and the denominator of another. There are a few ways to solve this, but the simplest is to get rid of fractions all together, by multiplying the whole equation by \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Think about what we've just done if \n" ); document.write( "\n" ); document.write( "We're now left with this equation, which is your bog standard quadratic. This one can be factorised quite easily. (I miss the days when every quadratic I had to solve was factorisable!)\r \n" ); document.write( "\n" ); document.write( "Multiplying out and tidying up gives\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, there isn't any coeficient in front of the x, and the constant term is negative, so we're looking at something like:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Where the question marks multiply to 72, and have a difference of 1. 8, and 9 look like good candidates. So that gives\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So from this we can read off that either \n" ); document.write( "\n" ); document.write( "Pluging both of these into the original equation shows they both work, so there's your answers.\r \n" ); document.write( "\n" ); document.write( "Hope that helps, \n" ); document.write( "Kev \n" ); document.write( " |