document.write( "Question 305408: a chemist is going to mix a 15% acid solution with a 45% acid solutionm how many liters of each solution should she mix in order to get 48 liters of a 20% acid solution? \n" ); document.write( "
Algebra.Com's Answer #218707 by nerdybill(7384) You can put this solution on YOUR website! a chemist is going to mix a 15% acid solution with a 45% acid solutionm how many liters of each solution should she mix in order to get 48 liters of a 20% acid solution? \n" ); document.write( ". \n" ); document.write( "Let x = liters of 15% acid solution \n" ); document.write( "then \n" ); document.write( "48-x = liters of 45% acid \n" ); document.write( ". \n" ); document.write( ".14x + .45(48-x) = .20(48) \n" ); document.write( ".14x + 21.6 - .45x = 9.6 \n" ); document.write( "21.6 - .31x = 9.6 \n" ); document.write( "-.31x = -12 \n" ); document.write( "x = -12/(-.31) \n" ); document.write( "x = 38.71 liters (amount of 15% acid solution) \n" ); document.write( ". \n" ); document.write( "Amount of 45% acid solution: \n" ); document.write( "48-x = 48-38.71 = 9.29 liters \n" ); document.write( " |