document.write( "Question 305460: The perimeter of a rectangle is 11 times its width. If the length of the rectangle is 54, find the width. \n" ); document.write( "
Algebra.Com's Answer #218684 by london maths tutor(243)\"\" \"About 
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Let's length be L and width be w \r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2L + 2w \r
\n" ); document.write( "\n" ); document.write( "L = 54 \r
\n" ); document.write( "\n" ); document.write( "2(54) + 2w = 11w \r
\n" ); document.write( "\n" ); document.write( "108 = 9w \r
\n" ); document.write( "\n" ); document.write( "w = 108/ 9
\n" ); document.write( "w = 12 \r
\n" ); document.write( "\n" ); document.write( "Width = 12
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