document.write( "Question 305460: The perimeter of a rectangle is 11 times its width. If the length of the rectangle is 54, find the width. \n" ); document.write( "
Algebra.Com's Answer #218684 by london maths tutor(243)![]() ![]() You can put this solution on YOUR website! Let's length be L and width be w \r \n" ); document.write( "\n" ); document.write( "Perimeter = 2L + 2w \r \n" ); document.write( "\n" ); document.write( "L = 54 \r \n" ); document.write( "\n" ); document.write( "2(54) + 2w = 11w \r \n" ); document.write( "\n" ); document.write( "108 = 9w \r \n" ); document.write( "\n" ); document.write( "w = 108/ 9 \n" ); document.write( "w = 12 \r \n" ); document.write( "\n" ); document.write( "Width = 12 \n" ); document.write( " |