document.write( "Question 305366: For a two digit numbers its digit in the ten’s place is twice the digit in the unit’s place. When 8 is subtracted from the number digits at both places are equal. Find the number? \n" ); document.write( "
Algebra.Com's Answer #218682 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = the 10's digit
\n" ); document.write( "Let y = the units digit
\n" ); document.write( "Let z = the digits after 8 has been subtracted
\n" ); document.write( "10x + y = \"the number\"
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "For a two digit numbers it's digit in the ten’s place is twice the digit in the unit’s place.
\n" ); document.write( "x = 2y
\n" ); document.write( ":
\n" ); document.write( "When 8 is subtracted from the number; digits at both places are equal.
\n" ); document.write( "10x + y - 8 = 10z + z
\n" ); document.write( "Replace x with 2y
\n" ); document.write( "10(2y) + y = 11z + 8
\n" ); document.write( "20y + y = 11z + 8
\n" ); document.write( "21y = 11z + 8
\n" ); document.write( "y = \"11%2F21\"z + \"8%2F21\"
\n" ); document.write( "The only value for z that gives an integer value for y, is 5
\n" ); document.write( "y = \"11%2F21\"(5) + \"8%2F21\"
\n" ); document.write( "y = \"55%2F21\"z + \"8%2F21\"
\n" ); document.write( "y = \"63%2F21\"z
\n" ); document.write( "y = 3
\n" ); document.write( "then
\n" ); document.write( "x = 2(3)
\n" ); document.write( "x = 6
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\n" ); document.write( "The number = 63
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\n" ); document.write( "Check: 63 - 8 = 55\r
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