document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4663>Question 4663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two angles are complementary and one angle is 3 less than twice the other angle, find the measure of the two angles. Write an equation and solve it to find the angles. You must use algebra and show your work.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2186 by </B><A HREF=/tutors/aboutme.mpl?userid=arunpaul><B>arunpaul(104)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arunpaul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the two angle are = A and B<BR>\n" );
document.write( "so Angle A + Angle B  = 90 degree\r<BR>\n" );
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document.write( "or A+ B = 90<BR>\n" );
document.write( "again as per question let A = B + 3<BR>\n" );
document.write( " putting the value of A in the above equation we have <BR>\n" );
document.write( "or B + 3 + B = 90<BR>\n" );
document.write( "or 2B + 3 = 90<BR>\n" );
document.write( "or 2B = 90- 3= 87<BR>\n" );
document.write( "B = 87/2 = 43.5 degree<BR>\n" );
document.write( "so A = 90 - 43.5 = 46.5 degree  (Ans) </SPAN>\n" );
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