document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305297>Question 305297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, one angle is 6 degrees more than the second angle. the third angle is 18 degrees more than the second angle. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218597 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the second angle be x\r<BR>\n" );
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document.write( "first angle will be x+6 \r<BR>\n" );
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document.write( "Third angle will be 18+(x+6)= x+24\r<BR>\n" );
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document.write( "x+x+6+x+24=180\r<BR>\n" );
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document.write( "3x+30=180\r<BR>\n" );
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document.write( "3x=150\r<BR>\n" );
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document.write( "x= 50  second angle\r<BR>\n" );
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document.write( "first angle = 56\r<BR>\n" );
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document.write( "third angle = 50+24= 74 deg\r<BR>\n" );
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document.write( " </SPAN>\n" );
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