document.write( "Question 305309: Here is the problem: The length of a rectangle is 4 meters longer than the width. If the area is 8 square meters, find the rectangle's dimensions. Round to the nearest tenth of a meter. I keep arriving at 4 m. by 1.5 m and that is NOT correct...Thank you in advance for your help! Amber \n" ); document.write( "

Algebra.Com's Answer #218586 by mananth(16946) $\"\"$ $\"About$

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Here is the problem: The length of a rectangle is 4 meters longer than the width. If the area is 8 square meters, find the rectangle's dimensions. Round to the nearest tenth of a meter. I keep arriving at 4 m. by 1.5 m and that is NOT correct...Thank you in advance for your help! Amber\r
\n" ); document.write( "\n" ); document.write( "let the width be x meters\r
\n" ); document.write( "\n" ); document.write( "length will be x+4 meters\r
\n" ); document.write( "\n" ); document.write( "x(x+4)= 8\r
\n" ); document.write( "\n" ); document.write( "x^2+4x-8=0\r
\n" ); document.write( "\n" ); document.write( "x1= -4+sqrt(16+32) / 2\r
\n" ); document.write( "\n" ); document.write( "x1= -4 +sqrt(48) /2\r
\n" ); document.write( "\n" ); document.write( "= 1.46 = 1.5\r
\n" ); document.write( "\n" ); document.write( "x2= -5.46\r
\n" ); document.write( "\n" ); document.write( "so 1.5 is the width \r
\n" ); document.write( "\n" ); document.write( "X+4 is the length = 1.5 +4 = 5.5 meters\r
\n" ); document.write( "\n" ); document.write( "5.5*1.46 = 8.03 square ,meters\r
\n" ); document.write( "\n" ); document.write( "Ananth\r
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