document.write( "Question 305266: A car left the house traveling north at 10 A.M. Another car left the house traveling south two hours later. If the cars traveled at the same rate and were 550 miles apart at 4 p.m., what was the rate of each car? \n" ); document.write( "

Algebra.Com's Answer #218565 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Write a separate equation or each car
\n" ); document.write( "Car traveling north:
\n" ); document.write( " $\"d%5B1%5D+=+r%5B1%5D%2At%5B1%5D\"$
\n" ); document.write( "Car traveling south:
\n" ); document.write( " $\"d%5B2%5D+=+r%5B2%5D%2At%5B2%5D\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+550\"$ mi
\n" ); document.write( " $\"r%5B1%5D+=+r%5B2%5D\"$ (call it $\"r\"$ )
\n" ); document.write( "Car 1 traveled north for $\"6\"$ hrs
\n" ); document.write( "Car 2 traveled south for $\"4\"$ hrs
\n" ); document.write( "------------------------------------
\n" ); document.write( " $\"d%5B1%5D+=+r%2A6\"$
\n" ); document.write( " $\"d%5B2%5D+=+r%2A4\"$
\n" ); document.write( " $\"d%5B2%5D+=+550+-+d%5B1%5D\"$
\n" ); document.write( " $\"550+-+d%5B1%5D+=+4r\"$
\n" ); document.write( " $\"550+-+6r+=+4r\"$
\n" ); document.write( " $\"10r+=+550\"$
\n" ); document.write( " $\"r+=+55\"$ mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( " $\"d%5B1%5D+=+6%2A55\"$
\n" ); document.write( " $\"d%5B1%5D+=+330\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"d%5B2%5D+=+4%2A55\"$
\n" ); document.write( " $\"d%5B2%5D+=+220\"$ mi
\n" ); document.write( " $\"330+%2B+220+=+550\"$ mi
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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