document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305229>Question 305229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> :49 It says: Solve by completing the square <BR>\n" );
document.write( "equation: m^2-25/2m=5/2 <BR>\n" );
document.write( "the 25/2 is a fraction and the \"x\" is on the side, and the 5/2 is a fraction as well. <BR>\n" );
document.write( "This is what I've tried so far: <BR>\n" );
document.write( "I moved the \"5/2\" to the other side of the equal sign to where it looks like this: <BR>\n" );
document.write( "m^2-25/2x-5/2=0 <BR>\n" );
document.write( "then I've tried to figure out how to square it  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218564 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m^2 - (25/2)m = 5/2\r<BR>\n" );
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document.write( "adding half of the 1st order coefficient, squared ___ m^2 - (25/2)m + (-25/4)^2 = 5/2 + (-25/4)^2\r<BR>\n" );
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document.write( "[m - (25/4)]^2 = 665/16\r<BR>\n" );
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document.write( "taking square root ___ m - (25/4) = ±[sqrt(665)]/4\r<BR>\n" );
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document.write( "m = [25 ± sqrt(665)]/4 </SPAN>\n" );
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