document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35736>Question 35736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation for a circle satisfying the given conditions\r<BR>\n" );
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document.write( "center(6,-5) passes through (1,7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21851 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the equation of a circle, you must know the center and the radius of the circle.  In this problem, you are given the center, but not the radius.  However, the radius is the distance between the center and the given point that is on the circle.  Use the distance formula to find this distance, which is the radius of the circle.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28+%281-6%29%5E2+%2B+%287-%28-5%29%29%5E2%29+ ALIGN=MIDDLE  ALT=\"r+=+sqrt%28+%281-6%29%5E2+%2B+%287-%28-5%29%29%5E2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r+=+sqrt%2825%2B+144%29+ ALIGN=MIDDLE  ALT=\"+r+=+sqrt%2825%2B+144%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=+sqrt%28169%29+ ALIGN=MIDDLE  ALT=\"r=+sqrt%28169%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+r=+13 ALIGN=MIDDLE  ALT=\"+r=+13\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, the equation of a circle with center at (h,k) and radius r is given by <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"+%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "In this case, it will be <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+13%5E2 ALIGN=MIDDLE  ALT=\"+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+13%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+169 ALIGN=MIDDLE  ALT=\"+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+169\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Some teachers require you to multiply this out, but this form is acceptable to me.  If your teacher wants it multiplied out, then by all means multiply away!!\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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