document.write( "Question 305135: the perimeter of a rectangle is 152m. The length is 4m more than twice the width. find the demensions \n" ); document.write( "
Algebra.Com's Answer #218499 by checkley77(12844)\"\" \"About 
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152=2L+2W
\n" ); document.write( "L=2W+4
\n" ); document.write( "152=2(2W+4)+2W
\n" ); document.write( "152=4W+8+2W
\n" ); document.write( "152=6W+8
\n" ); document.write( "6W=152-8
\n" ); document.write( "6W=144
\n" ); document.write( "W=144/6
\n" ); document.write( "W=24 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*24+4
\n" ); document.write( "L=48+4
\n" ); document.write( "L=522ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "152=2*52+2*24
\n" ); document.write( "152=104+48
\n" ); document.write( "152=152\r
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