document.write( "Question 305135: the perimeter of a rectangle is 152m. The length is 4m more than twice the width. find the demensions \n" ); document.write( "
Algebra.Com's Answer #218499 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 152=2L+2W \n" ); document.write( "L=2W+4 \n" ); document.write( "152=2(2W+4)+2W \n" ); document.write( "152=4W+8+2W \n" ); document.write( "152=6W+8 \n" ); document.write( "6W=152-8 \n" ); document.write( "6W=144 \n" ); document.write( "W=144/6 \n" ); document.write( "W=24 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*24+4 \n" ); document.write( "L=48+4 \n" ); document.write( "L=522ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "152=2*52+2*24 \n" ); document.write( "152=104+48 \n" ); document.write( "152=152\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |