document.write( "Question 305147: A cyclist is traveling 85 miles in 5 hours against the wind. He travels 174 miles in 6 hours with the wind. What is the rate of the still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #218490 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "85=(R-W)*5 AGAINST THE WIND.
\n" ); document.write( "85=5R-5W
\n" ); document.write( "5R=85+5W
\n" ); document.write( "R=(85+5W)/5
\n" ); document.write( "R=17+W
\n" ); document.write( "174=(R+W)6 WITH THE WIND.
\n" ); document.write( "174=6R+6W
\n" ); document.write( "6R=174-6W
\n" ); document.write( "R=(174-6W)/6
\n" ); document.write( "R=29-W
\n" ); document.write( "17+W=29-W
\n" ); document.write( "2W=29-17
\n" ); document.write( "2W=12
\n" ); document.write( "W=12/2
\n" ); document.write( "W=6 MPH.
\n" ); document.write( "R=17+6=23 THE SPEED OF THE BIKE IN STILL AIR.
\n" ); document.write( "R=29-6=23
\n" ); document.write( "PROOF:
\n" ); document.write( "85=(23-6)5
\n" ); document.write( "85=17*5
\n" ); document.write( "85=85
\n" ); document.write( "174=(23+6)*6
\n" ); document.write( "174=29*6
\n" ); document.write( "174=174\r
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