document.write( "Question 35734: Simplify. Assume that no radicands were formed by raising negaitve quantaties to even powers.\r
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Algebra.Com's Answer #21849 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Congratulations on writing your own equation box!! First off, you can make a single radical out of this\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29\"
\n" ); document.write( "\"sqrt%28%28128a%5E2b%5E4%29%2F%2816ab%29%29\" \r
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\n" ); document.write( "\n" ); document.write( "Next, reduce the fraction inside the radical. Notice that 16 goes into 128 about 8 times, and the \"a\" and \"b\" divide out leaving an \"8ab%5E3\" in the numerator.\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%288ab%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, sort this out and place in TWO separate square roots, where you will put all the PERFECT SQUARE factors in the first radical, and all the left over factors in the second radical. Notice that 8 has a perfect square that divides into it, which would be 4 (and the left over factor is 2), and \"b%5E2\" is a perfect square, which leaves factors of \"a\" and \"b\" left over.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%284b%5E2%29%2A+sqrt%282ab%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of the first radical, and leave the second one alone:
\n" ); document.write( "\"2b%2Asqrt%282ab%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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