document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35727>Question 35727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good evening, Would u help please with my Digit problem<BR>\n" );
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document.write( "   The ones digit of a whole number is 1 more than twice the tens digit. When the two digits are reversed, the new number is 4 less than twice the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21848 by </B><A HREF=/tutors/aboutme.mpl?userid=narayaba><B>narayaba(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=narayaba><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the tens digit of the original whole number be x the according to the problem the ones digit is one more than twice x hence the ones digit is 2x + 1\r<BR>\n" );
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document.write( "the value of original number is obtained as follows<BR>\n" );
document.write( "any number with A as unit digit and B as tens digit can we written as<BR>\n" );
document.write( "10*B+ A*1 since the place value of B is 10 and that of A is 1\r<BR>\n" );
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document.write( "similarly for the number with 2x+1 as ones digit and x tens digit<BR>\n" );
document.write( "we have the value of the number as 10x + 2x+ 1 = 12x + 1\r<BR>\n" );
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document.write( "if the digits are reversed then the new numbers unit digit is x and the tens digit is 2x+1\r<BR>\n" );
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document.write( "hence the value of the new number is 10*(2x+1)+x = 21x + 10\r<BR>\n" );
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document.write( "it is given the new number is 4 less than twice the original number\r<BR>\n" );
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document.write( "therefore we have 21x + 10 = 2*(12x+1) - 4\r<BR>\n" );
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document.write( "21x + 10 = 24x + 2 - 4<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "the original number is 12x+1 = 49 </SPAN>\n" );
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