document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=305072>Question 305072</A>: <I><SPAN STYLE=\"word-break: break-all;\">   Sorry if this is not the right topic, I have no idea what kind of problem this is:  If f(x)=2x+1 and g(x)=(x-1)/2, then f(g(x))= ?  Answer and steps for getting there would be much appreciated thanks to all for your help so far!<BR>\n" );
document.write( "Mike </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218454 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x)=2x+1 and g(x)=(x-1)/2, then f(g(x))= ?<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "f[g(x)] <BR>\n" );
document.write( "= f[(x-1)/2] <BR>\n" );
document.write( "= 2[(x-1)/2]+1 <BR>\n" );
document.write( "= x-1 + 1 <BR>\n" );
document.write( "= x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
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