document.write( "Question 304957: The perimeter of a rectangle is 30cm; the area of the rectangle is 50cm square. Find the length and width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Please help!
\n" ); document.write( "Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #218411 by scutechandni10(7)\"\" \"About 
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Perimeter is 30cm
\n" ); document.write( "Area= 50cm2
\n" ); document.write( "Now,form simultaneous equation;
\n" ); document.write( "2l+2w=30
\n" ); document.write( "l*w=50
\n" ); document.write( "l=50/w
\n" ); document.write( "substitute into first equation:
\n" ); document.write( "2(50/w)+2w=30
\n" ); document.write( "100/w+2w=30
\n" ); document.write( "find LCM of w and 1; that is w
\n" ); document.write( "Therefore; (100 + 2w square)/w = 30
\n" ); document.write( "Multiply by w both sides to cancel(to get rid of) the denominator
\n" ); document.write( "w * 100+ 2w square/w = 30 * w
\n" ); document.write( "Therefore; 100+2w square = 30w
\n" ); document.write( "2w^2 - 30w + 100 = 0
\n" ); document.write( "Now this becomes a quadratic equation;
\n" ); document.write( "a= 2 b=-30 c= 100
\n" ); document.write( " now you substitute the values of a b and c in the formula.\r
\n" ); document.write( "\n" ); document.write( " ORR
\n" ); document.write( "By factorization;
\n" ); document.write( "Splitting the middle term;
\n" ); document.write( "2w^2-30w+100=0
\n" ); document.write( "2w^2-20w-10w+100=0
\n" ); document.write( "(2w^2-20w)+ (-10w+100)=0
\n" ); document.write( "2w(w-10)- 10(w-10)=0
\n" ); document.write( "Either (2w+10) (w-10) = 0
\n" ); document.write( "2w+10=0 w-10=0
\n" ); document.write( "2w=-10 w=+10
\n" ); document.write( "w= -5
\n" ); document.write( "Note: Length or width cannot be in negative therefore length is 10cm and width is 5cm
\n" ); document.write( "Note: ^2 means \"square\"
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