document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304952>Question 304952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve this sum using algebra equation.\r<BR>\n" );
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document.write( "A famer had 240 more ducks then chickens at first.He sold half of the ducks.After that he had 150 more chickens than ducks .How many ducks had he at first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218399 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of chickens he has be x\r<BR>\n" );
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document.write( "ducks = 240+x\r<BR>\n" );
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document.write( "(240+x) -1/2(240+x)\r<BR>\n" );
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document.write( "So he has 1/2 (240+x) ducks\r<BR>\n" );
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document.write( "1/2 (240+x) +150 = x\r<BR>\n" );
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document.write( "120+1/2 x+150= x\r<BR>\n" );
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document.write( "240 +x +300 /2 = x<BR>\n" );
document.write( "540+x=2x\r<BR>\n" );
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document.write( "x=540 number of chickens\r<BR>\n" );
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document.write( "Number of ducks = 540+240=780\r<BR>\n" );
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