document.write( "Question 304957: The perimeter of a rectangle is 30cm; the area of the rectangle is 50cm square. Find the length and width of the rectangle.\r
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Algebra.Com's Answer #218393 by mananth(16946)\"\" \"About 
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2L+2W= perimeter = 30\r
\n" ); document.write( "\n" ); document.write( "L*w =Area = 50\r
\n" ); document.write( "\n" ); document.write( "L*W=50 l= 50/w\r
\n" ); document.write( "\n" ); document.write( "2L + 2W = 30\r
\n" ); document.write( "\n" ); document.write( "2*50/w +2W= 30\r
\n" ); document.write( "\n" ); document.write( "100/W + 2W=30\r
\n" ); document.write( "\n" ); document.write( "100+2W^2 / w = 30\r
\n" ); document.write( "\n" ); document.write( "100+2W^2= 30 W\r
\n" ); document.write( "\n" ); document.write( "2W^2-30W+100=0\r
\n" ); document.write( "\n" ); document.write( "W^2-15W+50=0\r
\n" ); document.write( "\n" ); document.write( "W^2-10W-5W+50=0\r
\n" ); document.write( "\n" ); document.write( "W(W-10)-5(w-10)=0\r
\n" ); document.write( "\n" ); document.write( "(W-5)(W-10)=0\r
\n" ); document.write( "\n" ); document.write( "W= 5 Or 10\r
\n" ); document.write( "\n" ); document.write( "The sides of the rectangle are 5 by 10 \r
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