document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=304896>Question 304896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Amy has 4 quarters, 3 dimes and 2 pennies. Betty had 1 dime. Amy gave 3 of her coins to Betty. Amy now had 2 cents more than betty. Whata 3 coins did Amy give to betty? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #218347 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=218347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amy has 4 quarters, 3 dimes and 2 pennies. Betty had 1 dime. Amy gave 3 of her coins to Betty. Amy now had 2 cents more than betty. Whata 3 coins did Amy give to betty?\r<BR>\n" );
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document.write( "Let x be the amount Amy gave to Betty.  Amy starts with $1.32 or 132 cents. Since Betty stated with 10 cents and needs 2 more cents to equal Amy's new amount we have:\r<BR>\n" );
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document.write( "132 - x = 10 + x + 2\r<BR>\n" );
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document.write( "2x = 132 - 10 - 2 <BR>\n" );
document.write( "2x = 120<BR>\n" );
document.write( "x = 60\r<BR>\n" );
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document.write( "Betty must have 2 quarters and one dime from Amy to equal 60 cents.\r<BR>\n" );
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